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3x^2=3888
We move all terms to the left:
3x^2-(3888)=0
a = 3; b = 0; c = -3888;
Δ = b2-4ac
Δ = 02-4·3·(-3888)
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46656}=216$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-216}{2*3}=\frac{-216}{6} =-36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+216}{2*3}=\frac{216}{6} =36 $
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